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Subject: Re: A testposition an CT15

Author: Roy Eassa

Date: 10:22:09 09/25/02

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On September 25, 2002 at 08:40:28, Volker Kniest wrote:

>On September 25, 2002 at 08:23:11, Oreopoulos Kostas wrote:
>
>>[D]4kr2/ppp3pp/3qP3/3p2B1/8/2N5/PPn1Q1PP/R3b2K w - - 0 1
>>
>>This position is from a simul Tal-Miller 1988...
>>The correct way to play is
>>1.Nb5! Qe5 2.h4! Qg3 3.Rd1 Rf2 4.Qf2! Bf2 5. Rd5 +-
>>


It is indeed a fascinating position.  Here's a look at some of the other
branches, using Fritz:

1.Nb5! Qe5!?

   [1...Qc5 2.b4 Qb6
      (2...Qc6? 3.Rd1! +-)
    3.Rd1 d4
      (3...Rf5 4.Rxd5! Rxd5 5.Qh5+ g6 6.Qxh7 forces mate)
    4.h3 Bg3
      (4...g6 5.Qe5 +-)
    5.Qd3! a6
      (5...Bf4 6.Qxh7 Bxg5 7.Qg6+ +-)
    6.e7 +-]

2.h4!

   [2.Rd1 c6!
      (2...Qxg5 3.Nxc7+ Ke7 4.Nxd5+ Kd6
         (4...Ke8 5.Qb5+ mates)
       5.e7 Re8 6.Nf6+ +-)
    3.h4
       (3.Bh4? Rf4 -+)
    3...Qb8! =]

2...Qg3

   [2...Rf5 3.Qxe5 Rxe5 4.Nxc7+ +-]

3.Rd1! Rf2

   [3...d4 4.Rd3 Rf2 5.Qh5+ g6 6.Rxg3 Rf1+ 7.Kh2 Bxg3+ 8.Kxg3 gxh5
    9.Nxc7+ Kf8 10.e7+ and mates]

   [3...c6 4.Rd3 Qb8 5.Rf3 +-]

4.Qxf2!

   [4.Nxc7+ Qxc7 5.Qb5+ Qc6 6.Rxd5 Rf6! =]

4...Bxf2

   [4...Qxf2 5.Nxc7+ Kf8 6.e7+ +-]

5.Rxd5! +-



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