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Subject: Re: New and final solution of the Monty Hall Dilemma

Author: Uri Blass

Date: 06:45:47 09/27/02

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On September 27, 2002 at 08:50:27, Gerrit Reubold wrote:

>On September 27, 2002 at 08:22:06, Sune Fischer wrote:
>
>>On September 27, 2002 at 08:14:28, Gerrit Reubold wrote:
>>
>>>Hi Sune,
>>>
>>>On September 26, 2002 at 14:47:32, Sune Fischer wrote:
>>>
>>>I disagree, I am sure it doesn't matter whether the host opens a door (with a
>>>goat) KNOWING where the car is or by SHEAR LUCK. The candidate should switch in
>>>either case, thus improving his winning odds from 1/3 to 2/3. Of course, if the
>>>host doesn't know and opens the door with the car (accidently), the game is over
>>>:-)
>>
>>Ok, well at least we agree that if he KNOWS he should switch.
>>
>>So suppose the host doesn't know, and the host opens a door to a goat.
>>
>>What does this tell us?
>>Well, since he didn't know, it means he either had a 50% probability of opening
>>to a goat, or a 100% probability.
>>
>>He gets 100% probability if we are sitting on the car, and he gets 50% if the
>>car is behind the one of the doors he had to choose from.
>>
>>The odds of picking a goat if you have 100% probability is higher than if you
>>only have 50% (obviously), okay?
>
>I don't care what that probability was _before_ he opened the door. The door
>with the goat is _now_ open.

Suppose for the discussion that the candidate also guess door 1
and the host always open door 3 in case that door 1 has  a goat.

If I understand correctly you say that the candidate should switch
and get probability of 2/3.

Do you agree?

Let assume case i means that the car is behind door i.

In case 1 the car is behind door 1 so the candidate win only if he does not
switch.
In case 2 the car is behind door 2 so the candidate win only if
he switchs.

In case 3 the car is behind door 3 so the host expose the car so there
is no game.

Do you agree?

The probability for every case is 1/3 before the game start.

Do you agree?


If we know that case 3 does not happen and this is what we know
after the host opened door 3 and found no car then it means
that there are only 2 cases and the probability for every case is
(1/3)/(2/3)=1/2.

Do you agree?

It mean that switching is going to give you probability 1/2

Do you agree?

I did not spend some minutes to try to understand
sune's post but I believe that he also understood the point.

Uri



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