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Subject: Re: Monty Hall: The Proof only for trials > n=3

Author: Sune Fischer

Date: 06:32:48 09/28/02

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On September 28, 2002 at 09:10:10, Rolf Tueschen wrote:

>On September 28, 2002 at 08:41:51, Sune Fischer wrote:
>
>>I think it is time to give in, actually it isn't very complicated at all:
>>
>>Assume the hosts always opens to a goat (by luck or not):
>>
>>You first pick a car (1/3), you switch and pick a car (0%)
>>You first pick a goat (2/3), you switch and pick a car (100%)
>
>First of all you made a mistake.Your firstline should read "pick a goat (0%)".
>
>Now I'll show you my version:
>
>You first pick a car (1/3), you stick and pick a car. (100%)
>You first pick a goat (2/3), you stick and pick a goat. (0%)===> 50% in all

How do you get 50%, it's either 1/3 or 2/3, those are you first guess chances.

>You first pick a car, you switch and pick a goat. (0%)
>You first pick a goat, you switch and pick a car. (100%) ===> 50 %in all

You have an error, it is twice (100%) and not (0%), it should read:

You first pick a car (1/3), you switch and win a goat. (100%)
You first pick a goat (2/3), you switch and win a car. (100%) ===> 200%????

Now you should be able to see the nonsense of the 50%, perhaps you want to write
200% now? :)

>Where is your problem to understand the 50% for one single trial? The
>differences with your added 1/ or 2/3 doesn't matter for the four possible
>cases.

My problem is that math is different from intuition, and then you should trust
math.

-S.



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