Author: Omid David
Date: 15:06:21 10/04/02
Go up one level in this thread
On October 04, 2002 at 17:27:05, Jeremiah Penery wrote:
>On October 04, 2002 at 16:51:38, Roy Eassa wrote:
>
>>On October 03, 2002 at 19:18:16, Jeremiah Penery wrote:
>>
>>>[D]8/7p/6pP/k4pP1/b1p1pP2/KpPpP3/1P1P4/7Q w - - 0 1
>>>
>>>Static evaluation is now 0 here. The solution is supposed to be Qd1 <bishop
>>>move> {Kb5 Qh5!} Qxb3. The problem in solving this is that the evaluation after
>>>the given line is negative for white, so it doesn't want to play the
>>>'sacrifice'. But I consider it a good result that it knows this is a draw since
>>>it can't make progress.
>>>Normal Crafty 18.15 says near +5, while making the wrong move.
>>>
>>
>>
>>A question about the above: what do you mean "the solution is supposed to
>>be..."? What solution? White cannot win with that line, right? But White can
>>draw a million different ways, right?
>>
>>I agree that there if Black blunders with 1.Qd1 Kb5?? then White indeed wins
>>with 2.Qh5! But barring blunders, what's better about Qd1 as opposed to any
>>other waiting move? The sacrifice for 2 pawns does not win AFAIK.
>
>The stuff I read about it said that Qd1 <bishop move> Qxb3 was supposed to win
>for white. But that may be wrong - it's very deep, and I haven't carefully
>analyzed. Still, most programs will evaluate this like +6 or more, even though
>it should be a draw.
No blockade-detecting algorithm should announce a draw in this position, since
the blockade can be "broken". And I think there might be a victory for white
hidden:
1.Qd1
A) 1... Kb5
2.Qh5
i) 2... gxh5
3.g6 hxg6 4.h7 white winning
ii) 2... Ka5
3.Qxg6 hxg6 4.h7 white winning
B) 1...Bc6 (or any other bishop move)
2. Qxb3 cxb3 3.Kxb3 unclear situation
Omid.
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