Author: Eran
Date: 00:16:09 10/05/02
Deep Fritz7 and Kasparov were unable to break through Berlin Defense, for it
sounded a very solid opening. What happned in the Kramnik Berlin Defense
openings was that he successfully opened a game with open e and d files,
exchanged queens and made simplification that were very good for Black according
to the opening principle. So I wondered how about White stopping solid Berlin
Defense by playing 4.Qe2 instead of 4.O-O.
Please see the two PGN games below as examples. In the games below, no open
game, no queens exchanged and no simplification occurrs. Therefore, the game is
balance but White can cramp Black a bit, right?
Is 4.Qe2 a better move? What do you think?
[D]r1bqkb1r/pppp1ppp/2n2n2/1B2p3/4P3/5N2/PPPPQPPP/RNB1K2R b KQkq -
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A. Analysis by Fritz7 (Under Fritz7 GUI) on Pentium III 1000 MHz and 128 MB
Hashtable
[Event "?"]
[Site "?"]
[Date "????.??.??"]
[Round "?"]
[White "Ruy Lopez"]
[Black "Berlin Defense"]
[Result "*"]
[ECO "C65"]
[Annotator "Eran"]
[PlyCount "22"]
1. e4 e5 2. Nf3 Nc6 3. Bb5 Nf6 4. Qe2 {Fritz 7:} 4... Bc5 5. Bxc6 dxc6 6. d3
Qd6 7. O-O Bg4 8. Be3 Nd7 9. Bxc5 Nxc5 10. Nbd2 O-O-O 11. b4 Nd7 {0.06/16} *
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B. Played by Ruffian (UCI under Arena 0.90) on Pentium III 1000 MHz and 128 MB
Hashtable
[Event "Computer Schach Partie"]
[Site "?"]
[Date "2002.10.05"]
[Round "?"]
[White "Ruffian_101"]
[Black "Ruffian_101"]
[Result "*"]
[ECO "C65"]
[Opening "Ruy Lopez"]
[Time "08:45:04"]
[Variation "Berlin defence"]
[TimeControl "0+180"]
1. e4 e5 2. Nf3 Nc6 3. Bb5 Nf6 4. Qe2 Bc5 5. Bxc6 bxc6 6. Nxe5
{(Nxe5 Qe7 Nd3 Ba6 e5 Nd5 0-0 Nb4 Na3 d6 Qe4 Bxd3 cxd3 Qxe5 Re1 Qxe4 Rxe4)
0.20/15 180}
Qe7
{(Qe7 Nd3 Ba6 e5 Nd5 0-0 0-0 Qg4 Nb4 Nxc5 Qxc5 d4 Qb6 Re1 Nxc2) -0.06/14 180}
7. Nd3
{(Nd3 Ba6 Nc3 Bd4 0-0 0-0 Re1 Rfe8 a3 Rab8 Qf3 Bxc3 dxc3 Nxe4 Bf4) 0.05/15 180}
Ba6
{(Ba6 Nc3 Bd4 0-0 0-0 Re1 Rfe8 a3 Rab8 Qf3 Bxc3 dxc3 Nxe4 Bf4) -0.06/15 180}
8. Nc3 {(Nc3 0-0 0-0 Rfe8) 0.01/15 180} O-O {(0-0 0-0 Rfe8) -0.01/14 180} 9.
O-O
{(0-0 Rfe8 Qd1 Bd4 Re1 d6 a4 Rab8 Ra3 c5 Nf4 Bxc3 Rxc3 Nxe4 Rce3) 0.02/14 180}
Rfe8
{(Rfe8 Qd1 Bd4 Re1 d6 a4 Rab8 Ra3 c5 Nf4 Bxc3 Rxc3 Nxe4 Rce3 Rb4) -0.02/14 180}
10. Qd1 {(Qd1 Bd4 Re1 d6 a4) 0.02/14 180} Bd4
{(Bd4 Re1 Rab8 a3 c5 Nf4) -0.03/14 180} 11. Re1
{(Re1 Rab8 b3 Qd6 e5 Bxe5 Nxe5 Rxe5 Rxe5 Qxe5) -0.02/14 180} Rab8
{(Rab8 a3 c5 Nf4 Qe5 d3 Bxc3 bxc3 Qxc3 Bd2 Qb2 c4 d6 Qe2) 0.00/13 180} 12. a3
{(a3 c5 Nf4 Qe5 d3 Bxc3 bxc3 Qxc3 Bd2 Qd4 Ne2 Qa4 c4 Qc6) 0.01/13 180} c5
{(c5 Nf4 Qe5 Nh3 c4 d3 cxd3 cxd3 Bxc3 Bf4 Qd4 bxc3 Qxc3 Rc1) 0.07/13 180} 13.
Nf4 {(Nf4 Qe5 Nh3 c4 d3 cxd3 cxd3 Bxc3 Bf4 Qd4 bxc3 Qxc3 Rc1) -0.07/12 83} *
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