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Subject: Statistical Proof for a win of Kramnik in the second game!

Author: Rolf Tueschen

Date: 16:41:46 10/05/02


1. Kramnik could draw against Fritz with Kramnik Black, so he is at least
equally strong.

2. On Sunday Kramnik has White!

So this is clear.

Kramnik has 1/3 for his draw with Black and he has 1/3 for his being White.

the other 1/3 is for Fritz.

Since 2/3 is more than 1/3, Kramnik must win by _force_, for the statistics see
the widely discussed Monty Hall Dilemma here and in CTF. Folks did prove that
the car is with certainty behind the other door, that is the same now with
chess!

Kramnik has 67% advantage strategically and therefore he must win. Finger
crossed!!! QED

Rolf Tueschen



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