Author: Jeremiah Penery
Date: 00:27:34 10/15/02
Go up one level in this thread
On October 14, 2002 at 09:44:06, Vincent Diepeveen wrote: >On October 14, 2002 at 07:05:42, Dave Gomboc wrote: > >>On October 13, 2002 at 15:35:12, Vincent Diepeveen wrote: >> >>>On October 13, 2002 at 14:40:12, James Swafford wrote: >>> >>>I wonder why. there is just one person ever in this whole >>>planet who said 12(6) = 18 ply, and that's robert hyatt. >> >>Bullshit -- I said this years ago, after asking a member of the DB team. > >>Hsu just said it himself too: > >>EeEk(* DM) kibitzes: next question: Seems like people wants to know >>what the exact meaning of ""12(6)" in the Deep Blue log files, can you >>explain this? >>CrazyBird(DM) kibitzes: 12(6) means 12 plies of brute force (not >>counting the search extensions & quiescence). > >by definition this means: it was 12 ply not counting search extensions >and qsearch. of course hardware search is part of that. > >>CrazyBird(DM) kibitzes: 6 means the maximum hardware search depth >>allowed. > >that's part of that 12 ply. If you interpret it different then that's >your problem and wrong. > >'brute force search' is everything including hardware. In fact hsu >even specified it for the technical gifted that it is just >EXCLUDING qsearch and excluding extensions. > >>CrazyBird(DM) kibitzes: this means that the PV could be up to 6 plies >>deeper before quiescence. > >*possibly* if it prints (6), the logs clearly show that 5(6) doesn't >show a 5 ply mainline. but < 5 Sometimes it will happen, so? I've seen Fritz display a one-move PV for many plies in a row, so just because they show a short PV occasionally doesn't mean much of anything. There is not a single 5(6) in the logs, so I take 4(5) instead. After wrong pondering I find mainlines of length: Game 1: 2, 2, 3, 4, 3, 5, 2, 5, 6, 3, 5, 15, 3, 4, 6, 3, 7 Game 2: 3, 7, 7, 5, 6, 6, 2, 7, 8, 4, 4, 7 Game 3: 2, 4, 6, 6, 7, 4, 6, 4, 6, 3, 3, 4, 4, 4, 7, 5, 3, 6, 13, 6, 7 Game 4: 2, 3, 9, 2, 5, 3, 6, 4, 7, 3, 15, 5, 6, 7, 3, 7, 12 Game 5: 3, 5, 6, 11, 5, 2, 7, 5, 9, 4, 9, 6, 6, 7, 10, 2, 7 Game 6: 14, 4, 2, 3 Total length 2: 10 Total length 3: 15 Total length 4: 13 Total length 5: 10 Total length > 5: 40 Average length: 5.45 (480/88) This _IS_ proof that n(n+1) does NOT show a mainline of length < n in the average case. Even if you want to take only the first 5 such outputs in a game, the average is 4.86. Go further and take only the first 3 - the average is still 4.66.
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