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Subject: Re: 0x88 vs 144 (or 12x12)

Author: Russell Reagan

Date: 19:37:59 10/26/02

Go up one level in this thread

On October 26, 2002 at 07:41:41, Ricardo Gibert wrote:

>No collision errors if the 64 bits are stored in the table.

That *might* be true if you had a perfect hash key generation algorithm, where
each pawn formation mapped to exactly 1 hash key, but that is not the case.

Russell

• Re: 0x88 vs 144 (or 12x12) [corrected] Ricardo Gibert 01:38:19 10/27/02
• Re: 0x88 vs 144 (or 12x12) Ricardo Gibert 22:37:13 10/26/02
  • Re: 0x88 vs 144 (or 12x12) Dann Corbit 21:46:03 10/27/02
    • Re: 0x88 vs 144 (or 12x12) Ricardo Gibert 22:54:35 10/27/02
      • Re: 0x88 vs 144 (or 12x12) Dann Corbit 11:28:41 10/28/02

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