Author: Robert Hyatt
Date: 18:50:20 11/10/02
Go up one level in this thread
On November 10, 2002 at 11:07:17, Ricardo Gibert wrote: >On November 10, 2002 at 07:40:33, José de Jesús García Ruvalcaba wrote: > >>On November 09, 2002 at 15:55:48, Ricardo Gibert wrote: >> >>> >>>9 rounds are too many for the number of participants playing in a swiss. You end >>>up with weird pairing toward the end of the tournament where a high ranked >>>program gets paired with some program ranked in the middle, because the high >>>ranked program has played all the programs ranked higher already. This makes the >>>last round a bit of an anticlimax. Yuck! >>> >>>It makes more sense to play 5 rounds of 2 games each for a total of 10 games. 5 >>>rounds are perfect for the number of contestants entered and now the pairings >>>will always make some sense particularly because color allocation will not be a >>>problem. You will also get more games played between the high ranked programs >>>which will lend more interest to the contest. >>> >>>To me the choice is clear cut. 5 rounds of 2 games each PLEASE! >> >>Last time there were like 50 participants (I do not remember the actual number), >>so five rounds are not enough. > >5 rounds at 2 games per round makes 10 games. How can 9 games be enough and 10 >games not be enough? Do you really expect a big tie for first place, because >"five rounds are not enough?" I assume you are talking about playing an opponent twice, once black and once white? That means you only have 5 different opponents in an event with 50 players. Not enough to get a valid winner in a swiss event, which needs at _least_ log2(entries) rounds to really find the "best" player...
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