Author: Robert Hyatt
Date: 20:56:24 11/10/02
Go up one level in this thread
On November 10, 2002 at 21:53:12, Bob Durrett wrote: >On November 10, 2002 at 21:50:20, Robert Hyatt wrote: > >>On November 10, 2002 at 11:07:17, Ricardo Gibert wrote: >> >>>On November 10, 2002 at 07:40:33, José de Jesús García Ruvalcaba wrote: >>> >>>>On November 09, 2002 at 15:55:48, Ricardo Gibert wrote: >>>> >>>>> >>>>>9 rounds are too many for the number of participants playing in a swiss. You end >>>>>up with weird pairing toward the end of the tournament where a high ranked >>>>>program gets paired with some program ranked in the middle, because the high >>>>>ranked program has played all the programs ranked higher already. This makes the >>>>>last round a bit of an anticlimax. Yuck! >>>>> >>>>>It makes more sense to play 5 rounds of 2 games each for a total of 10 games. 5 >>>>>rounds are perfect for the number of contestants entered and now the pairings >>>>>will always make some sense particularly because color allocation will not be a >>>>>problem. You will also get more games played between the high ranked programs >>>>>which will lend more interest to the contest. >>>>> >>>>>To me the choice is clear cut. 5 rounds of 2 games each PLEASE! >>>> >>>>Last time there were like 50 participants (I do not remember the actual number), >>>>so five rounds are not enough. >>> >>>5 rounds at 2 games per round makes 10 games. How can 9 games be enough and 10 >>>games not be enough? Do you really expect a big tie for first place, because >>>"five rounds are not enough?" >> >>I assume you are talking about playing an opponent twice, once black and once >>white? That means you only have 5 different opponents in an event with >>50 players. Not enough to get a valid winner in a swiss event, which needs >>at _least_ log2(entries) rounds to really find the "best" player... > >Assuming no draws? > >Bob D. Of course. But draws happen, and they get distributed over most of the players, so they don't hurt too much. If you have 32 players and play 5 rounds, draws mean "clear first" might rely on tie-breaks... But clearly 50 players would be better served by playing 10 rounds vs 10 different opponents, rather than five pairs of games against only 5 total opponents..
This page took 0 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.