Author: José Carlos
Date: 14:06:51 11/22/02
Go up one level in this thread
On November 22, 2002 at 15:30:51, Uri Blass wrote:
>On November 22, 2002 at 13:11:42, José Carlos wrote:
>
>>On November 21, 2002 at 04:48:15, Uri Blass wrote:
>>
>>>On November 20, 2002 at 19:02:49, Gian-Carlo Pascutto wrote:
>>>
>>>>On November 20, 2002 at 18:54:30, Omid David Tabibi wrote:
>>>>
>>>>>>Could you please compare (Adptv + small quiesc) vs (Vrfd +small quiesc) ?
>>>>
>>>>When I have more time.
>>>>
>>>>If you want more data, I expect others will post results
>>>>from their programs as well. Maybe those are more encouraging...
>>>
>>>I will post after I implement the code.
>>>I have a problem because I am not sure how to implement the code in movei:
>>>
>>>
>>>
>>>Movei does not use null move pruning when the remaining depth is 1.
>>>I have special pruning rules for that case
>>>The pseudo code of movei is:
>>>
>>>
>>>int alphabeta(int depth, int alpha, int beta)
>>>{
>>>1.depth=depth+extensions
>>>2.if (depth<=0) return quiescence()
>>>3.if pruning rules happen return beta(pruning rules happen mainly when depth=1)
>>>4.if repetition return 0
>>
>> Why don't you do repetition test in the first place? If this node yields a
>>repetition, you shouldn't return quiescence nor beta. Or am I missing something?
>
>I do not think that it is better.
>I think that repetition usually do not happen so I save time by not detecting
>repetition
>
>I think that not doing repetition first is faster and the demage in the worst
>case is detecting the repetition later when pruning rules do not happen.
>
>I did not see a case when movei did draw by repetition instead of checkmate
>and it seems to me that it cannot happen because the pruning rules are not going
>to prune when the score is checkmate and I had repetition detection in qsearch.
>
>Uri
I understand.
I still believe it's better to test repetition first, because it's very fast
(at least for me). However, the 50 move rule test is just a comparison, so
that's fast for everyone...
José C.
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