Author: Vincent Diepeveen
Date: 07:05:20 12/23/02
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On December 23, 2002 at 09:59:44, Sune Fischer wrote: what i meant to say is that it's a peanut to solve WAC 002 if you do not have the in quadrant rule. with the pawn on e3 still the white king is within the quadrant of the pawns. So it is amazing for me how some programs can solve this at 8 or 9 ply. Most commercials only solve this when they actually see a queen on the board for black which can't get captured (or gets recaptured to queen again). Best regards, Vincent >On December 23, 2002 at 09:34:12, Vincent Diepeveen wrote: > >>On December 23, 2002 at 09:31:16, Vladimir Medvedev wrote: >> >>>On December 23, 2002 at 09:17:49, Vincent Diepeveen wrote: >>> >>>>On December 23, 2002 at 08:33:09, Vladimir Medvedev wrote: >>>> >>>>if you remove pawn on e3, does it also plan rxb2 initially then? >>>> >>> >>>No, it can't. >> >>why not? >> >>2 pawns on 6th+7th row is strong ain't it? > >Rxb2? Rxb2 c3 Rb6+ Kg7 Ke3! >Of course if white didn't win the tempo with the check he would be dead. > >[D]8/7p/4pk2/5p2/p1p2P2/Pr1p1K2/1P1R3P/8 b - - 0 1 > >Hard thing to evaluate staticly. > >-S.
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