Author: Sune Fischer
Date: 03:31:58 12/26/02
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On December 26, 2002 at 06:24:53, Drexel,Michael wrote: >On December 26, 2002 at 05:17:03, Sune Fischer wrote: > >>On December 25, 2002 at 23:23:48, Drexel,Michael wrote: >> >>>[D] Q2Q2Q1/1R6/3BR3/3k3N/2RB2Q1/5R2/Q2Q2Bp/3N3K w - - 0 1 >>> >>>Problem: >>>White to move >>>If white gives check it has to be mate in one. >>>Find a legal position with the highest number of possible checks. >>> >>>I discovered this 5 years ago. Took me about 16 hours to find it. >>>I think it is possible to find a proof that it is not possible to find more: >>> >>>85 mates in one! :-) >> >>Are you sure, I "only" count 78 mates?? >> >>Mates ply 0........: 0 >>Mates ply 1........: 78 >>Mates ply 2........: 0 >>Mates ply 3........: 468 >>Mates ply 4........: 0 >>Mates ply 5........: 9538 >> >>how did you count them? >> >>>I must have been crazy. >> >>Yes, you will fit right in here :) >> >>-S. > >I think I havent used calculator or computer to count them. >I presume simpy like that: > >Rb7 14 >Rf3 14 >Re6 10 >Rc4 9 >Bd4 13 >Bd6 11 >Nd1 2 >Nh5 2 >Qa5 4 >Qg5 4 >Qe4 1 >Qf5 1 >------ >S 85 Rc4-c6 isn't mate, Kxc6 is possible, so Rc4 must be 8. Qa5 is only 3, Qa2-a5 and Kxc4 is legal. Probably others too :) -S.
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