Author: Robert Hyatt
Date: 18:30:56 01/15/03
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On January 15, 2003 at 19:30:14, Aaron Gordon wrote: >Here's a little bit of math to prove my point. This cpu speedup factor was from >Hyatt, by the way. The P3-1GHz vs P4-1.6GHz was tested here. Anyway, as I said >before the 8x1GHz P3 would be > P4-2.8x2 w/ SMT. Here's how. If a P3-1GHz = >P4-1.6GHz you can figure this... > >Lets take the total MHz into account. 8x1000 * 8.0 p3 GHz, * 1.6 = 12.8 P4 GHz. >Getting a speedup of 5.9 (1+(8-1)*0.7) you get 5.9 p3 GHz / 9.44 P4 GHz. >For the P4.. (1+(2-1)*.7) = 1.7x speedup, also add 30% for SMT. This comes out >to 2.21x speedup. Take 2.8 * 2.21 and you get 6.188 P4 GHz. >9.44GHz > 6.188GHz P4 GHz. 8x1GHz P3 would be over 52% faster. Except you overlook the PIII vs PIV xeon numbers I posted. My dual 2.8 is almost exactly twice as fast as my quad 700. The quad is PIII xeon, the dual is PIV xeon with SMT on.
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