Author: Anthony Cozzie
Date: 15:04:35 02/11/03
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On February 11, 2003 at 11:04:25, Vincent Lejeune wrote: > >How many time for your program to find Nxh3! >with the idea Rd5! > >[D]3r2k1/ppq2pp1/2b1p2p/8/5n2/2P4P/PP3PP1/RN2QBK1 b - - 0 1 1...Qb6 2. b3 Qc5 3. h4 Qd5 4. c4 Qh5 5. g3 = (0.42) Depth: 8 00:00:04.88 2046kN 1...Qb6 2. b3 Qc5 3. c4 e5 4. g3 Nh5 5. Qc3 Ra8 = (0.40) Depth: 9 00:00:12.25 5855kN 1...Qa5 2. Kh2 Qf5 3. b4 Qd5 4. Qe3 Bb5 5. Qxf4 Bxf1 6. g3 = (0.44) Depth: 10 00:00:30.70 15151kN 1...Qa5 2. Kh2 Qf5 3. b4 Qe4 4. Qxe4 Bxe4 5. Kg3 g5 6. h4 Kg7 = (0.52) Depth: 11 00:01:02.25 31440kN 1...Qa5 2. Kh2 Qf5 3. b4 Nxh3 4. Qe5 Qxe5 5. Kxh3 + (1.02) Depth: 12 00:01:15.44 38041kN 1...Qa5 2. Kh2 Qf5 3. Na3 Nxh3 4. f3 Nf4 5. Nc4 Qh5 6. Kg1 Qc5 7. Kh2 Nd3 8. Bxd3 = (1.15) Depth: 12 00:01:52.90 57601kN 1...Nxh3 2. gxh3 Qf4 3. Bg2 Qg5 4. f3 Bxf3 5. Qf2 Bxg2 6. Qxa7 Bxh3 7. Kf2 + (1.65) Depth: 13 00:02:28.58 75668kN 1...Nxh3 2. gxh3 Qf4 3. Qe2 Bf3 4. Qe3 Qxe3 5. fxe3 Rd1 6. Kf2 Be4 7. a4 Rxb1 8. Ra2 = (1.83) Depth: 13 00:03:18.16 101497kN 1...Nxh3 2. gxh3 Qf4 3. Qe3 Qxe3 4. fxe3 Rd1 5. Kf2 Be4 6. Bc4 Rxb1 7. Rxb1 Bxb1 8. Kf3 e5 = (1.88) Depth: 14 00:05:19.74 167435kN a hard one for zappa :( and it also sees some funky way to trade queens and end up with an extra pawn. anthony
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