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Subject: Re: Detecting repetition in a search......

Author: Robert Hyatt

Date: 05:32:26 10/01/98

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On October 01, 1998 at 05:10:30, Dan Newman wrote:

>On October 01, 1998 at 03:18:58, Bruce Moreland wrote:
>
>>
>>On October 01, 1998 at 00:25:44, James Robertson wrote:
>>
>>>How do programs detect draws by repetition in a search? I can think of many
>>>possible ways, but they all seem really slow. How do most programs quickly
>>>detect draws by repetition?
>>
>>You have a hash key.  You have a transposition table.
>>
>>1) You can set a flag in your transposition table when you enter a node, and
>>clear it when you leave the node.  If you encounter a flag that's already set,
>>it's a rep draw.  You have to be careful not to kill your hash entry somehow,
>>there is tremendous potential for bugs.
>>
>>2) You can make a new hash table, a small one, and store the hash key in that
>>when you enter a node, and clear it when you leave.
>>
>>3) You can create a list of hash keys that represent positions that have
>>occurred between now and between the capture or pawn move, and iterate.  This
>>isn't as slow as it sounds, for reasons that I don't understand, but it may get
>>really bad in some pathological cases such as when you are near a 50-move draw.
>>
>
>This is what I currently do.  I too don't really understand why it's
>so cheap--it doesn't even show up when I do a profile.  I suspect
>that most of the time there's an irreversible move not so far back.
>It should be really bad in those pathological cases though...
>
>I once either saw or read about a trick to make this technique a bit
>less expensive.  The idea is to maintain a small array of counts
>(say 256 elements or so) indexed by a portion of the hashcode.
>Every time you enter a node you increment the array element that is
>selected by the current hashcode (and decrement it when you leave).
>If the resultant count after incrementing is 2 or more, then you
>*may* have a repetition and can do the usual scan of the hashcode
>list to confirm it.  If the resultant count is only 1, then you know
>you don't have a repetition and can forgo the more expensive test.
>The counts should be reset when irreversible moves are made at the
>root.
>
>>You have to be careful to take into account the en-passant square and the
>>castling flags in some circumstances.
>>
>>Without castling and en-passant, chess would be a lot simpler to program.
>>
>
>It would, wouldn't it...  Add to that the weird way pawns move and
>capture, pawn promotion, and the notion of being "in check".
>
>>You will get bugs no matter what you do.
>>
>>bruce
>>
>
>Dang.  I suspected as much.
>
>-Dan.


One other trick... if you handle the 50-move rule, is that you search backward
from the current repetition entry, but you only go back for as many entries as
the value of your 50-move rule counter indicates...  since many captures or
pawn pushes occur in the search, this cuts off this "loop" very quickly most
of the time...



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