Author: Steffen Basting
Date: 13:41:09 02/19/03
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On February 19, 2003 at 16:18:54, Charles Worthington wrote: >On February 19, 2003 at 16:13:58, Steffen Basting wrote: > >>Hi! >>No, I would say Martin is right. You can do that with rather practical numbers: >> >>One processor, ht disabled: 1.000 nps. >>=> Two processors, ht disabled: 2.000 nps. >> >>One processor, ht enabled: 1160 nps (ht disabled + 16%). >>=> Two processors, ht enabled: 2.320 nps. >> >>and 2.000 * 1.16 = 2.320, so your speed up is 16% for both cpus. >> >> >>Regards, Steffen > > >actally the speedup is doubled when you are dealing with dual processors. You >are using reverse mathematics to arrive at an incorrect answer. I honestly think >Dr. Hyatt knows his math. There's no doubt that Dr. Hyatt knows his math - I just cannot see the "bug" in my example. If the speed-up increases in the way you describe (n proc * 16%), it would mean that with 16 processors ht enabled you arrive at 256%. So you are faster than > 32 processors with ht disabled. This doesn't seem to be correct... Regards, Steffen
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