Author: Uri Blass
Date: 06:36:09 02/22/03
Go up one level in this thread
On February 22, 2003 at 09:16:07, Uri Blass wrote: >On February 22, 2003 at 08:54:30, Rolf Tueschen wrote: > >>I read 6: Ikarus 3.5 / 6 2b= 13w+ 1w= 4b= 3w- 14b+. >> >>So that means that Ikarus although playing the placed 1, 2, 3, 4 progs, it could >>get full points against the last and pre-last. Placed om 14 and 13. >>Is this ok? Something seems to be wrong or biased. Point is that a game against >>14 is a SURE win. That is as if a top program after a loss or two draws got a >>point for free. Note Ikarus had 2,5 pts before playing Matador with 0.5 pts. >> >>Could some expert explain why such things are still possible? >> >>Rolf Tueschen > >Can you suggest another pairing without repeating the sam game twice? > >Matador already played against all the programs that scored less than 50% >It had to play against a program that scored at least 50%. > >Uri I can add that Matador drew with a program that drew with a program that drew with a program that drew with a program that drew with a program that won the leader Fritz. I have the following results based on the table. Patzer-Matador (round 1) 1/2-1/2 Patzer-Comet (round 6) 1/2-1/2 Diep-Comet (round 3) 1/2-1/2 Anaconda-Diep (round 4) 1/2-1/2 Anaconda-Shredder (round 6) 1/2-1/2 Shredder-Fritz (round 5) 1-0 Note that based on this record I have a better result against Kasparov so it does not prove that Matador has practical chances against Fritz but I think that the number of games are too small even to be sure that Fritz has a sure win against Matador so I see no basis to the claim that a game against 14 is a sure win and all the beginning of the post has nothing to do with it. Even in case that a program lose all the first 5 games in a tournament there is no evidence for the claim that it has no chances. Uri
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