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Subject: Re: Pairing question about Ikarus

Author: Tony Werten

Date: 04:17:50 02/23/03

Go up one level in this thread


On February 22, 2003 at 16:58:12, Robert Hyatt wrote:

>On February 22, 2003 at 09:29:47, Rolf Tueschen wrote:
>
>>On February 22, 2003 at 09:25:16, Robert Hyatt wrote:
>>
>>>On February 22, 2003 at 08:54:30, Rolf Tueschen wrote:
>>>
>>>>I read 6: Ikarus     3.5 /  6    2b= 13w+  1w=  4b=  3w- 14b+.
>>>>
>>>>So that means that Ikarus although playing the placed 1, 2, 3, 4 progs, it could
>>>>get full points against the last and pre-last. Placed om 14 and 13.
>>>>Is this ok? Something seems to be wrong or biased. Point is that a game against
>>>>14 is a SURE win. That is as if a top program after a loss or two draws got a
>>>>point for free. Note Ikarus had 2,5 pts before playing Matador with 0.5 pts.
>>>>
>>>>Could some expert explain why such things are still possible?
>>>>
>>>>Rolf Tueschen
>>>
>>>
>>>Too few programs, too many rounds.
>>
>>Also, many progs get a "good" result and that is also a good side-effect we
>>should consider. What would be the optimal number of rounds for 14 participants?
>>
>>Rolf Tueschen
>
>optimal number of rounds is log2(N) rounded up to the next integer value.
>In this case 4 rounds, is optimal, 5 acceptable.

That might be true in general, but depends on the participants. When 8 programs
are very equal in strength, you want at least 7 rounds to make sure that there
is at least a little chance they have played each other.

Tony




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