Author: Mike Byrne
Date: 06:59:34 02/23/03
Go up one level in this thread
On February 23, 2003 at 07:17:50, Tony Werten wrote: >On February 22, 2003 at 16:58:12, Robert Hyatt wrote: > >>On February 22, 2003 at 09:29:47, Rolf Tueschen wrote: >> >>>On February 22, 2003 at 09:25:16, Robert Hyatt wrote: >>> >>>>On February 22, 2003 at 08:54:30, Rolf Tueschen wrote: >>>> >>>>>I read 6: Ikarus 3.5 / 6 2b= 13w+ 1w= 4b= 3w- 14b+. >>>>> >>>>>So that means that Ikarus although playing the placed 1, 2, 3, 4 progs, it could >>>>>get full points against the last and pre-last. Placed om 14 and 13. >>>>>Is this ok? Something seems to be wrong or biased. Point is that a game against >>>>>14 is a SURE win. That is as if a top program after a loss or two draws got a >>>>>point for free. Note Ikarus had 2,5 pts before playing Matador with 0.5 pts. >>>>> >>>>>Could some expert explain why such things are still possible? >>>>> >>>>>Rolf Tueschen >>>> >>>> >>>>Too few programs, too many rounds. >>> >>>Also, many progs get a "good" result and that is also a good side-effect we >>>should consider. What would be the optimal number of rounds for 14 participants? >>> >>>Rolf Tueschen >> >>optimal number of rounds is log2(N) rounded up to the next integer value. >>In this case 4 rounds, is optimal, 5 acceptable. > >That might be true in general, but depends on the participants. When 8 programs >are very equal in strength, you want at least 7 rounds to make sure that there >is at least a little chance they have played each other. > >Tony You just described a round robin which is totally different - if you have 8 programs and 7 rounds, you play a round robim and every player will play each other once. The formula is for use in a swiss tournament.
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