Author: Andrew Williams
Date: 04:42:19 04/10/03
Go up one level in this thread
On April 10, 2003 at 06:35:07, Uri Blass wrote:
>On April 09, 2003 at 23:56:54, Russell Reagan wrote:
>
>>So...who wants to explain how this works? I don't know how it works, but it
>>finds all of the solutions to the 8 queens problem.
>>
>>#include <stdio.h>
>>int v,i,j,k,l,s,a[99];
>>void main(void){
>>for(s=8;*a-s;v=a[j*=v]-a[i],k=i<s,j+=(v=j<s&&(!k&&!!printf(2+"\n\n%c"-(!l<<!j),"
>>#Q"[l^v?(l^j)&1:2])&&++l||a[i]<s&&v&&v-i+j&&v+i-j))&&!(l%=s),v||(i==j?a[i+=k]=0:++a[i])>=s*k&&++a[--i]);
>> printf("\n\n");
>>}
>
>I do not understand this code because my C knowledge is not enough.
>
>What is *a-s
>
>I understand that j*=v is j=j*v butI do not understand the meaning when * is at
>the beginning of the command.
>
>I never used it.
>
>Uri
a is a pointer. the statement you mentioned subtracts s from whatever integer a
is pointing at. the result is not stored, but whether it is zero or not is used
to control the for loop. i've not looked at the rest of the code, only at the
single line you mentioned.
AW
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