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Subject: How many top programs will play the correct Qe3+ in this position ?

Author: Jorge Pichard

Date: 14:23:14 04/12/03


How many programs can see that by forcing the exchange of queens that the pawns
ending is easily winning

Here Botvinnik calculated a straightforward way to win by exchanging off the
queens:

[D]8/kp6/P5p1/2p1p3/2PpP3/3P3Q/4q3/6K1 b - - 0 1


1... Qe3+ 2. Qxe3 dxe3 3. axb7 Kxb7 4. Kg2 Kb6 5. Kf3 Ka5 6. Kxe3 Kb4 7. Kd2 g5

now Black can win easy.




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