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Subject: Re: needing advice on new dual processor computer

Author: Vincent Diepeveen

Date: 05:32:39 07/08/03

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On July 08, 2003 at 08:24:54, George Sobala wrote:

>On July 08, 2003 at 06:52:43, Vincent Diepeveen wrote:
>
>>Speedup as it is in all the ICCA journals from the 80s and onwards is the number
>>of times you are faster out of n processors when compared to 1 processor of such
>>a system.
>>
>>So if i would get the blessed efficiency of 15% out of 500 processors that is
>>
>>0.15 * 500 = 75 times speedup
>>
>>However to compare it to the speed of a K7 1Ghz it is interesting to express it
>>in Ghz in this case: 37.5 Ghz
>>
>>So it effectively then 37.5 times faster than a K7 at 1 Ghz, assuming that K7
>>has a hashtable of 250GB.
>>
>>Most programmers talk always about speedup, but that's for a fixed amount of
>>cpu's they always have. Like 2.
>>
>>However with many cpu's i cannot always test with the same amount of CPUs so
>>speedup efficiency is a better form then to measure than speedup.
>>
>>Best regards,
>>Vincent
>
>That assumes that "speedup efficiency" is a constant across n processors, for
>any size of n. Is it? Seems very improbable.

I see many post here a 'x' % speedup caused by killermoves and other ordering
stuff that changes the b.f. and therefore exponentially influences the tree.

What i trivially make is a graph of how the efficiency goes from 1 to n where n
is at maximum 500. You won't find bigger machines with openMP and such latencies
than that on the planet.





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