Author: Uri Blass
Date: 02:06:16 07/17/03
Note that the name of the arrays that I have is different but I replaced the names to make it easy to understand the problem. I have an array A[64][8] I want to replace it by 8 arrays A0[64],A1[64],...A7[64] when A[i][j]=Aj[i] What is the best way to do it? I already added the arrays A0...A7 except the fact that I have different names. Today movei update both A0...A7 and A. I do not want to update A but to use Aj[i] that always has the same value as A[i][j]. There are cases when I call directly A3[square] and it should be faster then calling A[square][3] but there cases when I call Aj[square] when j is not the same every time. I can do it by switch command but the question is if this is the right way to go or if there is a faster way. I thought that it may be possible to have some union when A0,A1,....A7 means the same as A but I do not see exactly how to do it. Uri
This page took 0.01 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.