Author: Uri Blass
Date: 06:03:33 07/17/03
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On July 17, 2003 at 07:01:10, Dave Gomboc wrote: >On July 17, 2003 at 05:06:16, Uri Blass wrote: > >>Note that the name of the arrays that I have is different but I replaced the >>names to make it easy to understand the problem. >> >>I have an array A[64][8] >> >>I want to replace it by 8 arrays A0[64],A1[64],...A7[64] when A[i][j]=Aj[i] >> >>What is the best way to do it? > > >I think you want something like > > typedef /* your type here */ element_type; > > element_type big_array[8][64]; > const element_type zeroth_array [64] = big_array[0]; > const element_type first_array [64] = big_array[1]; > const element_type second_array [64] = big_array[2]; > const element_type third_array [64] = big_array[3]; > const element_type fourth_array [64] = big_array[4]; > const element_type fifth_array [64] = big_array[5]; > const element_type sixth_array [64] = big_array[6]; > const element_type seventh_array[64] = big_array[7]; > >Then you can refer either to big_array[0][n] or to zeroth_array[n]. > >The syntax is probably not exactly correct, my machine is busy so I didn't put >it through a compiler. You are right that the syntex is not correct. When I use int instead of element type I get the error array initialization needs curly braces Maybe I need the following syntex except using significant names to the array and not big_array, zeroth_array,...: int big_array[8][64]; int * const zeroth_array = big_array[0]; int * const first_array = big_array[1]; Uri
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