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Subject: Re: Traversing bitboards in a symmetrical way

Author: Tim Foden

Date: 03:46:31 08/04/03

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On August 04, 2003 at 06:26:08, Zach Wegner wrote:

>On August 04, 2003 at 06:11:20, Gerd Isenberg wrote:
>
>>Hi all,
>>
>>One common search/evaluation test is to compare the search of a position with
>>it's mirrored position.
>>
>>There is one principle problem related to bitboard traversal in move-generation.
>>
>>Black pieces and targets are traversed in an other order than the "mirrored"
>>pieces and targets, regardless if one uses bsf or bsr and the square-bitindex
>>mapping.
>>
>>Lets take some white pawns with following bit indicies: b2(9),d2(11) and c3(18).
>>With bsf you'll find them in ascending order: b2,d2,c3. Now with "mirrored"
>>black pawns on b7(49),d7(51),c6(42) we will foreward scan the ascending c6,b7,d7
>>squares.
>>
>>Even if there is further move sorting, the different initial order of generated
>>moves in mirrored positions implies different search trees - and therefore
>>slightly different search results.
>>
>>How do you deal with this behaviour in your bitboard based program?
>>I ignore it so far.
>>
>>One possible solution with x86-64 is to use the fast "bswap reg64" instruction
>>(direct path,1 cycle) before scanning black pieces or targets for movegen.
>>"bswap" mirrors the bits rankwise (8 becomes 1, 7 become 2...) and a remirror of
>>the scanned bit index is a simple xor with 0x38.
>>
>>According to the sample above we mirror the black b7,d7,c6 pawns to b2',d2',c3'
>>and we get the same order as with original white pawns: b7,d7,c6.
>>
>>One drawback is of course the need of a color2move paramter for bitScan - or
>>separate black/white traversal.
>>
>>Any remarks or implementaion hints?
>>
>>Regards,
>>Gerd
>
>What I have always done, which avoids this problem, is to use either MSB or LSB
>for removing a piece depending on which side of the board it is most likely to
>be on. e.g. for white pawns, use LSB; for black pawns, use MSB. I dont know if
>this helps, but it couldn't hurt.

Yes, I basically do the same, for the same reason... it is a very simple
optimisation.  For the white pieces I always use bsf, and for the black pieces I
always use bsr.  This also has the added advantage of solving the problem that
Gerd is talking about.

Cheers, Tim.



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