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Subject: Re: Show this position to your engine

Author: Dieter Buerssner

Date: 07:24:06 08/23/03

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On August 22, 2003 at 14:35:51, John Merlino wrote:

>>8/3p1P2/3Pp3/2p1P2K/p1p3P1/PpP3p1/1P3pP1/6k1 w - - 0 1
>>
>>1. f8=R f1=Q 2. Rxf1+ Kxf1 3. g5 Kxg2 4. g6 Kh2 5. g7 g2 6. g8=Q g1=Q 7. Qxg1+
>>Kxg1 8. Kg6 Kf2 9. Kf6 Ke2 10. Ke7 Kd2 11. Kxd7 Kc2 12. Kxe6 Kxb2 13. d7 Kxa3
>>
>>and at this juncture:
>>
>>[D]8/3P4/4K3/2p1P3/p1p5/kpP5/8/8 w - - 0 14
>>
>>white has to underpromote again in order to win...
>>
>>Mihaly
>
>Fair enough.
>
>However, I think that asking an engine to find an underpromotion 27 ply away
>from the current position is a bit much. AND it looks like finding the
>underpromotion from THIS position requires at least a dozen ply search. So,
>you're asking the engine to search 40 plies from the initial position in order
>for it to give a correct answer.
>
>Can you tell me an engine that can do this? I looked at the other replies so far
>and none of them have done it.

Yace shows it after a long search for a while:

4218848324 5:07:50   0.34 27.  1. f8=R f1=Q 2. Rxf1+ Kxf1 3. g5 Kxg2 4. g6 Kf1
                               5. g7 g2 6. g8=Q g1=Q 7. Qxg1+ Kxg1 8. Kg5 Kf2
                               9. Kf6 Ke1 10. Ke7 Kd2 11. Kxd7 Kc2 12. Kxe6
                               Kxb2 13. d7 Kxa3 14. d8=Q b2 15. Qd5 b1=Q 16.
                               Qxc4 Qb3 17. Kd5 Kb2 18. e6 a3 {HT} {0}
 780537524 5:27:51   0.74 28++ 1. f8=R f1=Q 2. Rxf1+ Kxf1 3. g5 Kxg2 4. g6 Kf1
                               5. g7 g2 6. g8=Q g1=Q 7. Qxg1+ Kxg1 8. Kg5 Kf2
                               9. Kf6 Ke1 10. Ke7 Kd2 11. Kxd7 Kc2 12. Kxe6
                               Kxb2 13. d7 Kxa3 14. d8=R Kb2 15. Kd5 Kc2 16.
                               e6 b2 17. Rb8 a3 18. e7 b1=R 19. e8=Q Rxb8 {341}
1960815916 5:54:59   1.59 28t  1. f8=R Kxg2 2. Kh4 f1=Q 3. Rxf1 Kxf1 4. Kxg3
                               Ke2 5. g5 Kd3 6. g6 Kc2 7. g7 Kxb2 8. g8=Q Ka1
                               9. Qc8 b2 10. Qxd7 b1=Q 11. Qxe6 Qd3+ 12. Kg4
                               Qxc3 13. Qd5 Qe3 14. d7 Qg1+ 15. Kf5 c3 16. e6
                               c2 17. Qe5+ Ka2 18. Qe2 Kb3 {HT} {0}

Then it switches to 1...Kxg2 as the black defense, which should mean, that the
2nd underpromotion is understood. Before, the score decreased from iteration to
iteration.

Regards,
Dieter





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