Author: Tim Foden
Date: 06:55:25 09/10/03
Go up one level in this thread
On September 10, 2003 at 09:36:20, Uri Blass wrote:
>On September 10, 2003 at 09:16:04, Tim Foden wrote:
>
>>On September 10, 2003 at 08:45:22, Uri Blass wrote:
>>
>>>I found that my program printed the numbers 0 and 1 when it did the following
>>>code without printing mistake or mistake1.
>>>
>>>zobpawnkey[hply]=zobpawn;
>>>if (nodes==663719)
>>>{
>>> if (zobpawnkey[hply]!=zobpawn)
>>> printf("mistake");
>>> if ((zobpawnkey[hply]&1)!=(zobpawn&1))
>>> printf("mistake1");
>>> printf(" %d %d ",(zobpawn&1),(zobpawnkey[hply]&1));
>> ^^ ^^ these expect int, not __int64.
>>
>>If using Microsoft's compiler system, you should use %I64d instead.
>>
>>Cheers, Tim.
>
>I understand that %d does not give me the right value but the fact that it
>prints different numbers for identical numbers still seems strange to me.
This can be explained. If the number (zobpawn&1) is 1, then the stack will
contain 4 32bit int values that make up the 2 64 bit ones:
0x00000001
0x00000000
0x00000001
0x00000000
printf( "%d %d" ). will just use the first 2 of these 32 bit numbers, thus it
will print 1 and 0.
These are the kinds of code pitfalls that are common to printf and scanf.
Cheers, Tim.
>
>Uri
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