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Subject: Re: Doubling of thinking time, greater benefits for dedicated computers?

Author: Dann Corbit

Date: 19:27:14 11/20/03

Go up one level in this thread

On November 20, 2003 at 22:21:46, Dann Corbit wrote:

>On November 20, 2003 at 19:50:12, Uri Blass wrote:
>
>>On November 20, 2003 at 18:57:24, J. C. Boco wrote:
>>
>>>Doubling the processor speed or the time for thinking adds about 80 points to
>>>the SSDF-computer-ratings.  But PC's are already running so fast that doubling
>>>their speed might mean searching at 15ply instead of 14ply.
>>
>>How do you get it?
>>
>>Based on the ssdf list even being 3 times faster does not give 80 elo.
>>A1200 is often more than 3 times faster than K6-450
>>
>>Uri
>
>This query:
>SELECT a.engine, (a.Elo - b.Elo)/(1200.0/450.0) AS EloDiff
>FROM Ssdf AS a, Ssdf AS b
>WHERE a.Engine = b.Engine
>
>And
>   a.Hardware like "*1200 MHz*"
>
>And
>   b.Hardware like "*450 Mhz*"
>
>Order by  (a.Elo - b.Elo)/(1200.0/450.0) Desc
>
>Returns this result set:
>
>engine	EloDiff
>Gandalf 4.32h	50.625
>Crafty 18.12/CB	50.25
>Gandalf 5.0	42
>Fritz 7.0	42
>Deep Fritz 7.0	41.25
>Rebel Century 4.0	40.125
>Hiarcs 8.0	36.75
>Chess Tiger 14.0 CB	32.25
>Gambit Tiger 2.0	27.375
>Deep Fritz	25.125
>Junior 7.0	22.875
>Chess Tiger 15.0	20.625
>Shredder 5.32	20.25
>
>And this query:
>
>SELECT sum((a.Elo-b.Elo)/(1200/450))/count((a.Elo-b.Elo)/(1200/450)) AS
>EloDiffAverage
>FROM Ssdf AS a, Ssdf AS b
>WHERE a.Engine=b.Engine And a.Hardware Like "*1200 MHz*" And b.Hardware Like
>"*450 Mhz*";
>
>Gives this result:
>34.7307692308
>
>~35 ELO per doubling seems like what we might expect.  Give or take a large
>error bar.

This query:
SELECT sum((a.Elo-b.Elo)/(450/200))/count((a.Elo-b.Elo)/(450/200)) AS
EloDiffAverage
FROM Ssdf AS a, Ssdf AS b
WHERE a.Engine=b.Engine And a.Hardware Like "*450 MHz*" And b.Hardware Like
"*200 MMX*";

Gives this result:
32.0888888889

This query:

SELECT sum((a.Elo-b.Elo)/(200/90))/count((a.Elo-b.Elo)/(200/90)) AS
EloDiffAverage
FROM Ssdf AS a, Ssdf AS b
WHERE a.Engine=b.Engine And a.Hardware Like "*200 MMX*" And b.Hardware Like "*90
Mhz*";

Gives this result:
36.18

Looks like it holds pretty steady.

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