Author: K. Burcham
Date: 13:48:10 11/21/03
I think you could answer this for me Dann. When we set hash at 64 megs and the program ends up needing more than this, is it your understanding that the program keeps the same assigned addresses on the ram as the original hash setting and just writes over the top of it? OR Do you think that as the program needs more than 64 megs it fills this and starts assigning new addresses in ram separate from original hash setting and does not write over the top of the original 64 megs and then will fill as much ram as the operating system will allow it to? kburcham
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