Author: Eugene Nalimov
Date: 13:56:43 11/17/98
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Sorry, with 8-bytes IEEE doubles counter will cease to increment when it'll reach (roughly) 2**53 == 10**16, not 10**308. Of course it's still better than 4*10**9 with 32-bit unsigned integer. Eugene On November 17, 1998 at 15:10:48, Dann Corbit wrote: >On November 17, 1998 at 13:03:38, Bruce Moreland wrote: >[snip] >>An acceptable solution is to use a 64-bit number to count nodes. On current >>machines, this will delay the advent of this problem for something on the order >>of a million years. >A double would also be peachy. On some machines, floating point is as fast or >faster than integer math. Unless you added them in batches, at some point a >double would not increment any more (that pesky DBL_EPSILON). But with an IEEE >8 byte double, you should be able to hold about 10^308, which should hold down >the fort for a while.
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