Author: Albert Bertilsson
Date: 12:58:54 12/14/03
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I have a database with all the perft(3) positions (8902 positions). The clients calculate perft(8) for each position, this gives a perft(11) for the whole problem. For perft(12) the client have to do perft(9) calculations or the database could have all the perft(4) positions. Duplicate positions are handled be the server, when the result arrives for a specific position the result is written for all positions that are identical. /Regards Albert
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