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Subject: Re: Perfect example

Author: scott farrell

Date: 05:40:13 03/13/04

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On March 13, 2004 at 07:33:08, Andrew Wagner wrote:

>In this position: [d]rn1qk1nr/pp3ppp/4p1b1/3p4/1b1P1BP1/2N1P3/PP3P1P/R2QKBNR w
>KQkq - 1 8
>
>
>I got this output:
>
>Trueno(C) kibitzes: depth=1; score=-63; Time=0; nodes: 111; PV=g4-g5
>Trueno(C) kibitzes: depth=2; score=788; Time=0; nodes: 105; PV=g4-g5 b4-e7
>Trueno(C) kibitzes: depth=3; score=751; Time=1; nodes: 2521; PV=g1-f3 b4-d6
>a1-b1
>Trueno(C) kibitzes: depth=4; score=34; Time=3; nodes: 6987; PV=g1-f3 d8-a5 d1-a4
>a5-a4
>Trueno(C) kibitzes: 12 seconds, 810 nps
>Trueno(C) kibitzes: MoveOrder%: 81
>Trueno(C) kibitzes: Hash Percentage: 7
>Trueno(C) kibitzes: Hash probes: 62105
>Trueno(C) kibitzes: Hash hits: 4459

looks to me like a qsearch problem.

also, nodes in ply 2 look a little odd, being less than ply 1 - its not
neceessarily wrong, just strange.

Try reversing all colours, and run eval, try reversing stm and running eval,
they all should be equal, this sometimes shows you errors in your eval function.

810 nps is a problem, are you checking the time at each node? you should only
check every x nodes, checking the clock is very very slow.

Scott



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