Author: Sune Fischer
Date: 14:47:40 04/15/04
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On April 15, 2004 at 15:40:30, Gerd Isenberg wrote: >>But since the relation between bb and 0x88 is: >>0x88 = bb shl 1-(bb and 7), you can also use it for bb. >> >>Tony > >Nice trick to save the additional and of the rank ;-) Same trick, only on the upper 3 bits: 0x88 = bb + (bb & ~7) -S. >Cheers, >Gerd
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