Computer Chess Club Archives


Search

Terms

Messages

Subject: Re: pre-chess

Author: Telmo C. Escobar

Date: 13:14:15 05/16/04

Go up one level in this thread


On May 16, 2004 at 14:28:48, Marc Bourzutschky wrote:

>In a book review at www.chesscafe.com there is a discussion of an older version
>of Fischer Random Chess, called pre-chess.
>
>The main difference between FRC and pre-chess is that in pre-chess black and
>white can have different piece arrangements on the first row.  The only
>constraints are that each side has to have opposite colored bishops, and that
>castling is only allowed like in classical chess (i.e., white can only castle if
>the king is on e1, and there is a rook on a1 or h1, etc).  However, it is not
>required that the starting position must allow castling.
>
>How many game theoretically different positions are there in pre-chess?  I know
>of 4 different suggestions, 2 by famous and 2 by less famous chess enthusiasts:
>
>Max Euwe: 4,147,200
>Noam Elkies: 8,294,400
>Paul Epstein: 5,317,600
>Marc Bourzutschky: 5,149,368
>
>Which one is correct, or all they all wrong?
>
>-Marc


 This is a trivial exercise in elementary combinatorics. The natural to solve
it, I think, is the following:

 as the pawns are in the second (and seventh) file, the problem is just how many
ways there are to place the eight White pieces. Let us name this number as "W".
As the Black pieces are to be placed independently, the final solution will be W
squared  (by comparison, in Fischerandom the solution will be just W).

 Let us speculate about W:

 as both bishops, poor thinks, have to be on different colored squares, there
are 4x4=16 ways to place them. On the remaining 6 squares, there are 6x5 ways to
place king + queen. Finally, in the four remaining squares, we must compute how
many ways to place two rooks and two knights. Obviously it suffices to compute
the rooks, and this is how many ways to select two squares, and this is six.

 In short, W=16 x 30 x 6= 16 x 6 x 30= 96 x 30= (100 - 4) x 30= 3000- 120= 2880.

 The final solution, W squared, is (3000 - 120) squared, in other words 9000000
+ 14400 - (6000 x 120) = 9000000 + 14400 - 720000 = 9000000 - 7000000 - 20000 +
14400 = 8300000 - 20000 + 14400 = 8280000 + 14400 = 8294400.  I don't have a
calculating machine at hand, so I had to make the calculations the human way, as
easy as possible.

 So that guy Noam Elkies was right, the other three were wrong.

 Max Euwe was a world chess champion (not significant information) and also he
held a PH.D. in math (very significant). So it's astonishing he was wrong about
this trivial problem. The other three I didn't know about.

 The calculation took less than one minute and one just have to know a minimal
high school algebra to solve it. It will make a useful exercise for teenage
students.

  Telmo



This page took 0 seconds to execute

Last modified: Thu, 15 Apr 21 08:11:13 -0700

Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.