Author: Dieter Buerssner
Date: 13:52:39 05/16/04
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On May 16, 2004 at 16:24:53, Telmo C. Escobar wrote: >On May 16, 2004 at 16:15:31, Dieter Buerssner wrote: > >> >>(8*4*6*5*3*2)^2 >> >>Intention: First B has 8 squares, second B has four squares (the ones remaining >>with different color) >> > > Wrong! This is the kind of mistake my students usually make. > > You are counting each possibily twice. For instance, imagine your "first" >bishop is placed at a1, and your "second" bishop is at b1. The position of >bishops you obviously are counting twice :) You are right. Note, that I calculated correctly (you can see it from my post, where I further on calculated with 2880). I also thought correctly (you may believe this or not ... I copied and pasted it from my calculator app - and hit the wrong line). I really meant ((8*4*6*5*4*3*2)/2^3)^2 2^3, as you explained it, because we have 2 Bs, Ns and Rs. I hope the remaining of my post was more correct. Regards, Dieter
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