Author: Fabien Letouzey
Date: 07:30:50 06/07/04
Go up one level in this thread
>Like when I tried this,
>void main()
>{
> typedef unsigned __int64 u64;
> u64 r;
> r=1<<36;
> printf("%I64u",r);
> getchar();
>}
>The r value was printed as 0.Also for other numbers >36 its printing as 0.Is
>this correct value that r is having?
Yes, you shift "1" which is a 32-bit integer (int).
It should be r = 1ui64 << 36;
I suppose "1i64u" or "(unsigned __int64) 1" also work.
Fabien.
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