Author: Uri Blass
Date: 17:51:35 06/11/04
Go up one level in this thread
On June 11, 2004 at 20:39:33, Joshua Shriver wrote:
>
>Parse your argv data.
>
>Believe argv[0] is the filename of the executable being run.
>
>int main(int argc, char *argv[])
>{
>
> printf("%s\n", argv[0]);
>
> return 0;
>}
Based on Dann Corbit's post I cannot trust it so I think that I will not try to
use it inspite of the fact that now it works because tomorrow with a new
compiler it may stop to work.
Here are Dann Corbit's words:
This information from the C-FAQ may be relevant:
19.31: How can my program discover the complete pathname to the
executable from which it was invoked?
A: argv[0] may contain all or part of the pathname, or it may
contain nothing. You may be able to duplicate the command
language interpreter's search path logic to locate the
executable if the name in argv[0] is present but incomplete.
However, there is no guaranteed solution.
Uri
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