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Subject: Re: A Very Good Test Position For Dedicated Units

Author: Daniel Jackson

Date: 14:18:26 06/30/04

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On June 30, 2004 at 16:53:50, Stuart Cracraft wrote:

>On June 30, 2004 at 08:56:28, Daniel Jackson wrote:
>
>>[D]2r4k/ppqbpp1p/3p1npQ/3R4/2r1P1P1/2N2P2/PPP1N3/1K5R w
>>
>>
>>I tested this position with the Mach III Master back in 1989, it took about
>>1hr.09min. to find Rf5!! with the double threat of Rxf6! and Nd5!
>>
>>Daniel
>
>Woops -- I take that back. Hit it on the 11th ply though possibly not
>for the right reason but unknown without the PV. Took about 4 hours 40
>minutes. This box is about 3-4x slower than the P4 models out now so I'd
>expect about 1 hour for the solution. That's a big difference from the
>tiny cpu's Dan and Kathe Spracklen were running. I wouldn't expect
>this problem to be much of an issue for today's crop of PC programs,
>certainly nothing like even an hour.  Probably just a few minutes.
>Wish there were other takers for this challenge. This is getting boring.

Yes, I thought a few others would plug in this position...maybe some will when
they see it...

Yes, Dan Spracklen was a very good programmer in his day! An hour is good when
the hardware is only a mere 68000 running at 16mgh and written in 8-bit code!:o)
>
>NULLMV TT(524288) Alpha=-1985 Beta=15 Maxdepth=15 MaxTime=9999999
>1. e2d4  v=-961 t=0.00 nps=89k(0k) ha=10% bc=90% br=Inf
>2. g4g5 f6h5  v=-969 t=0.05 nps=81k(3k) ha=13% bc=88% br=18.5
>3. g4g5 f6h5 e2d4  v=-945 t=0.09 nps=89k(7k) ha=35% bc=86% br=1.0
>4. g4g5 f6h5 h1d1 h5g7  v=-965 t=0.45 nps=77k(34k) ha=24% bc=86% br=8.6
>5. g4g5 f6h5 h1d1 d7c6 d5d4
>        v=-955 t=1.94 nps=80k(155k) ha=28% bc=88% br=4.1
>6. g4g5
>        v=-979 t=16.05 nps=82k(1310k) ha=23% bc=83% br=9.5
>7. d5d3 d5d3 c4c3 b2c3 f6e4 g4g5
>        v=21 t=43.67 nps=75k(3287k) ha=24% bc=81% br=2.0
>7. >>d5d3 c4c3 b2c3 f6e4 h6h7
>        v=21 t=51.97 nps=76k(3935k) ha=27% bc=82% br=0.3
>8. g4g5
>        v=-964 t=401.30 nps=76k(30339k) ha=22% bc=85% br=42.1
>9. d5d4
>        v=22 t=1106.21 nps=74k(81321k) ha=21% bc=83% br=2.0
>10. g4g5
>        v=-950 t=5059.02 nps=72k(365625k) ha=21% bc=-23% br=5.6
>11. d5f5
>        v=26 t=16689.57 nps=76k(1270544k) ha=4% bc=6% br=2.9
>
>Stuart



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