Author: Rolf Tueschen
Date: 12:35:07 07/18/04
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On July 18, 2004 at 14:40:01, Rémi Coulom wrote: >Hi, > >I compiled a new version of the tool that I distributed yesterday. This one can >deal with larger numbers of games. I tested that it works for a 6000-game match, >so that should be enough for everyone. You can get it at this address: >http://remi.coulom.free.fr/WhoIsBest.zip > >The only difference with yesterday's program is that it is compiled with gcc >instead of msvc. the "long double" type is 80 bit in gcc and 64 in msvc. The >additional accuracy is enough to solve underflow problems. > >Concerning Joachim's problem, here is the output of the program: > > This program evaluates the likelihood that program A is better than >program B, based on the result of two matches played against the same >opponent (or set of opponents). The number of games played in each of >these matches does not have to be the same. If playing against a set >of opponents, the proportion of each opponent should be the same in each >match. > The likelihood is estimated by Bayesian inference, assuming an uniform >prior distribution of the probabilites of losing and winning. > The resulting integral is estimated with a Monte-Carlo method. It may >take a long time to converge when the number of games is large (>100). >The computation can be interrupted at any time with Ctrl-C. > >A wins = 197 >A losses = 108 >A draws = 95 > >B wins = 189 >B losses = 130 >B draws = 81 > >P(A>B) = 0.890434 (600000000 iterations) > >Rémi Rémi, excuse-moi stp, if you look at the two programs and their numbers, you can see without too much calculation that the p of A>B can never me .89... No way! To say that I don't need formulas. These numbers are much too small. I guess that you then let a routine program run through thousands and more iterations. Yes, but that is NOT chess, that is mathematics. And as you know mathematics never can construct or allow statements about reality of chess or any other field. Rolf
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