Author: Paul Clarke
Date: 04:07:07 07/26/04
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On July 24, 2004 at 12:56:11, Matthias Gemuh wrote: > >a) memcpy(&ChsStrct->PlyData[ChsStrct->nPly+1], > &ChsStrct->PlyData[ChsStrct->nPly], sizeof(PLYDATA)); > >b) ChsStrct->PlyData[ChsStrct->nPly+1] = ChsStrct->PlyData[ChsStrct->nPly]; > > >Will either of these copy the array element of type struct PLYDATA ?. >Any special thing to mention concerning speed, padding, aligninment ? If you're writing C, either should work. I'd expect the assignment to be no slower, and possibly faster as it gives the compiler more information to work with. I also find (b) to be clearer, so I can't see any reason to use (a). If you're writing C++ then there's anothe drawback to (a): if PLYDATA needs to override the assignment operator then using (a) will almost certainly cause bugs.
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