Author: George Tsavdaris
Date: 10:51:37 01/14/05
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On January 14, 2005 at 13:03:20, Dan Wulff wrote: >Hi! > >I'm trying to figure out the total number of TB's there will be with kxxkxx (3 >vs 3 pieces) once they are all created. I have come to 120, but I am not sure I >did the math correctly. > >Can someone provide me with the correct number, and possibly a list of the >classes ?? The formula is: f( (f(x+1 , 2) + 1) , 2) where f(a,b) = a!/(b!(a-b)!) and a! = 1·2·3·....·(a-1)·a and x= number of pieces wanted for the tablebase. So since now x=5 (P,N,B,R,Q) we have: f( (f(6,2)+1) , 2) = f(16 , 2) = 120 So you are right................
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