Author: Dieter Buerssner
Date: 15:46:52 01/14/05
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On January 14, 2005 at 13:03:20, Dan Wulff wrote: >I'm trying to figure out the total number of TB's there will be with kxxkxx (3 >vs 3 pieces) once they are all created. I have come to 120, but I am not sure I >did the math correctly. 120 is correct. If you are really interested, have a look at these two posts of Guido Antonelli (author of tbe GAFS library - an alternative to Nalimov TBs): http://chessprogramming.org/cccsearch/ccc.php?art_id=223640 http://chessprogramming.org/cccsearch/ccc.php?art_id=221160 I also had some private conversation with Guido, where we discussed some easier formulas to calculate the number of different TBs. Perhaps I can still find it. I wanted to write an article about it here in CCC, but did not find the time. I believe, I guessed more or less the formulas, and Guido could prove it. >Can someone provide me with the correct number, and possibly a list of the >classes ?? What do you mean by classes? Regards, Dieter
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