Author: Vincent Diepeveen
Date: 04:49:38 01/15/05
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On January 14, 2005 at 13:51:37, George Tsavdaris wrote: >On January 14, 2005 at 13:03:20, Dan Wulff wrote: > >>Hi! >> >>I'm trying to figure out the total number of TB's there will be with kxxkxx (3 >>vs 3 pieces) once they are all created. I have come to 120, but I am not sure I >>did the math correctly. >> >>Can someone provide me with the correct number, and possibly a list of the >>classes ?? > >The formula is: f( (f(x+1 , 2) + 1) , 2) > >where f(a,b) = a!/(b!(a-b)!) and a! = 1·2·3·....·(a-1)·a >and x= number of pieces wanted for the tablebase. > >So since now x=5 (P,N,B,R,Q) we have: > >f( (f(6,2)+1) , 2) = f(16 , 2) = 120 > >So you are right................ in diep's listing please look: number 146..265 that's : 265 - 146 + 1 = 120 :) 146..
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