Author: Oreopoulos Kostas
Date: 11:21:03 01/24/05
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Sorry but if i am not mistaken ( and i am not) defining a problem as Hard NP is not a matter of finite or infinite space. Its whether the algorithm is O(n) or O(2^n). The main difference i see from a typical trav salesman prob is that in chess we have evaluation functions, which as a result lower the branching factor of the space. The question of NP hard is if we can make the evaluation functions so efficient that the Best move question breaks down to an O(n) algorithm. It is obvious that i dont mean about searching the space. THis is the obvious solution to every [at first sight] NP problem.
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