Author: Olaf Jenkner
Date: 13:53:03 01/25/05
Go up one level in this thread
> > >but to store a 32 piece tablebase would be a lot 'smaller'. > >might a 2.5 by 2.5 kilometre crystal do the trick ? > > >duncan We have about 10^42 positions to store. The third root is 10^14. Take a 1000^3 km crystal. You must store 100000 positions at one millimeter. 100 at one micrometer. Maybe, the crystal was too big. Perhaps 99,999999% of the legal positions will never be necessary to compute the tree. Than we can take a smaller cube. OJe
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