Author: Thomas Mayer
Date: 10:11:19 02/01/05
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Hi Uri, On February 01, 2005 at 12:58:24, Uri Blass wrote: >On February 01, 2005 at 12:20:30, Thomas Mayer wrote: > >>Hi, >> >>just a hypotetic question: >>Let's think that the bishop side has several bishops, all of the same colour. >>The question is now: when not any of the bishops alone can stop the pawn is it >>possible to create a position where they all together can stop it anyway ? >>Or is it sufficent to say that it is a win when the lone pawn was checked in the >>TBs against each bishop and both checks say that it is won ? >> >>I hope you understand what I mean -> I can not really explain it to myself... :) >> >>a possible example: >> >>[D] 3K2b1/7P/8/8/8/8/b2k4/8 w - - 0 1 >> >>without the bishop on b2 this would be of course won and TBs give back a win >>when we check the pawn against both bishops... and of course according to five >>man this position is also won... the question is if it is possible to create a >>position with the above mentioned circomstances which is draw ?! >> >>Greets, Thomas >> >>P.S.: You see, I am working on Quarks endgame... :) > > >I am not sure if this is the example that you look for but 2 bishop can stop the >pawn by Be8 pin when one bishop cannot do it. > >Uri > >[D]k7/5P2/2b3K1/8/b7/8/8/8 b - - 0 1 Thank you ! That was exactly what I was searching for... seems that I did forget about pins... it also shows that it is won when the king is on another coloured field then the bishops and the above mentioned circomstances are true... does it ? Still thinking... Greets, Thomas
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