Author: Vincent Diepeveen
Date: 11:02:18 02/01/05
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On February 01, 2005 at 12:20:30, Thomas Mayer wrote: You mean like this? [D]8/8/P4b2/2K3k1/8/8/8/8 b - - >Hi, > >just a hypotetic question: >Let's think that the bishop side has several bishops, all of the same colour. >The question is now: when not any of the bishops alone can stop the pawn is it >possible to create a position where they all together can stop it anyway ? >Or is it sufficent to say that it is a win when the lone pawn was checked in the >TBs against each bishop and both checks say that it is won ? > >I hope you understand what I mean -> I can not really explain it to myself... :) > >a possible example: > >[D] 3K2b1/7P/8/8/8/8/b2k4/8 w - - 0 1 > >without the bishop on b2 this would be of course won and TBs give back a win >when we check the pawn against both bishops... and of course according to five >man this position is also won... the question is if it is possible to create a >position with the above mentioned circomstances which is draw ?! > >Greets, Thomas > >P.S.: You see, I am working on Quarks endgame... :)
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