Author: Tim Foden
Date: 12:49:38 02/22/05
Go up one level in this thread
On February 22, 2005 at 15:45:02, Tom Likens wrote:
>On February 22, 2005 at 14:10:10, Tim Foden wrote:
>
>>On February 22, 2005 at 08:35:07, Andrew Wagner wrote:
>>
>>>Hi all.
>>>I got sidetracked this morning by an interesting chess programming problem. It
>>>took me a couple hours, but I think I have a working algorithm -- haven't tested
>>>yet though. Anyway, I got to wondering if others would approach it the same way.
>>>So I thought I'd make a little competition of it. Post your code here, and I'll
>>>pick the program I like best and shower praise and adulation on its author. If
>>>people like this challenge, maybe I'll do one each month or something. Anyway,
>>>here's the one I did this morning:
>>>There are 64 x 63 = 4032 ways to put a black knight and white knoght both on a
>>>chess board. Write a program -- from scratch -- to generate FENs for each of
>>>these positions. The FENs should look something like: Nn6/8/8/8/8/8/8/8 w - - 0
>>>1.
>>>
>>>I think my code will wind up weighing in at around 60-70 lines of C. Can you do
>>>better?
>>
>>Here's my attempt, although I did squidge the lines together a bit (20 lines) :)
>>
>>#include <stdio.h>
>>int main( int, char** ) {
>> for( int i = 0; i < 64; i++ ) {
>> for( int j = 0; j < 64; j++ ) {
>> if( i == j ) continue;
>> for( int cnt = 0, k = 0; k < 64; k++ ) {
>> if( k && (k & 7) == 0 ) printf( "/" );
>> if( k == i || k == j ) {
>> if( cnt != 0 ) { printf( "%d", cnt ); cnt = 0; }
>> printf( k == i ? "N" : "n" );
>> } else {
>> cnt++;
>> if( (k & 7) == 7 ) { printf( "%d", cnt ); cnt = 0; }
>> }
>> }
>> printf( " - - 0 1\n" );
>> }
>> }
>> return 0;
>>}
>>
>>Cheers, Tim.
>
>Tim,
>
>You could make this slightly shorter by declaring main void and getting rid
>of that "return 0" at the end! ;-)
>regards,
>--tom
Yep... but that seems like taking it a bit too far for me :)
Cheers, Tim.
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