Author: Reinhard Scharnagl
Date: 03:25:09 03/03/05
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Hi Dieter, I will try to make a sharper approach to calculate, how many legal positions should be possible on an 8x8 board with all pieces used. I had not thought, that 100 bits might be sufficient, but I had to learn that it really could be. in each file there will be 15 possible valid pP configurations: 01: -p----P- 02: -p---P-- 03: -p--P--- 04: -p-P---- 05: -pP----- 06: --p---P- 07: --p--P-- 08: --p-P--- 09: --pP---- 10: ---p--P- 11: ---p-P-- 12: ---pP--- 13: ----p-P- 14: ----pP-- 15: -----pP- covering castling right could be reache by supporting three additional places for each king with the meaning: original place with left, right or double castling rights. placing all pawns: 15^8 placing white king + castling rights: 35 = (32+3) placing black king + castling rights: 34 = (31+3) placing white w Bishop in average: 15 placing white b Bishop in average: 15 placing black w Bishop in average: 14 placing black b Bishop in average: 14 placing 2 white Knights: 26*25/2 placing 2 black Knights: 24*23/2 placing 2 white Rooks: 22*21/2 placing 2 black Rooks: 20*19/2 placing white Queen: 18 placing black Queen: 17 side to move 2 e.p. is possible or not 2 affected e.p. file 8 -------------------------------------------- estimated possibilities 8*35*34*(15^10)*(7^2)*26!/16! this is meaning about 102.03 bits. Reinhard.
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